Answer
Answer: A Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then, (X*14*2/100)+{(13900-X)*11*2/100} = 3508.
28x/100 + (13900*22)-(x*22)/100 = 3508.
28x/100 + 305800-22x/100 = 3508.
28x+305800-22x/100 = 3508.
Now,
28x+305800-22x=3508*100.
28x-22x=350800-305800.
6x=45000.
x=45000/6.
x=7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Answer Answer: 10 Explanation: Just use the concept of divisibility of 11 and get the answer.
As number is 13b7 is divisible by 11 the difference of alternate digit
must be zero or 11, so 1+b = 3+7 or (1+b) - (3+7) = 0. So you got b = 9.
A+8 = b, a+8 = 9 so a = 1, hence a+b = 10.